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-x^2+14x-2x^2+6x=28
We move all terms to the left:
-x^2+14x-2x^2+6x-(28)=0
We add all the numbers together, and all the variables
-3x^2+20x-28=0
a = -3; b = 20; c = -28;
Δ = b2-4ac
Δ = 202-4·(-3)·(-28)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-8}{2*-3}=\frac{-28}{-6} =4+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+8}{2*-3}=\frac{-12}{-6} =+2 $
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